Het volgende stukje tekst is genomen uit een artikel geschreven door David Baker.
LIGHTENING FLYWHEELS - AN EXERCISE IN ROTATIONAL DYNAMICS
When the flywheel of a car is lightened it can have a great effect on acceleration - much more than just the weight saving as a proportion of the total vehicle weight would account for. This is because rotating components store rotational energy as well as having to be accelerated in a linear direction along with the rest of the car's mass. The faster a component rotates, the greater the amount of rotational kinetic energy that ends up being stored in it. The engine turns potential energy from fuel into kinetic energy of motion when it accelerates a vehicle. Any energy that ends up being stored in rotating components is not available to accelerate the car in a linear direction - so reducing the mass (or more properly the "moment of inertia") of these components leaves more of the engine's output to accelerate the car. It can be useful to know how much weight we would need to remove from the chassis to equate to removing a given amount of weight from the flywheel (or any other rotating component). There is more than one way of solving this equation - we can work out the torque and forces acting on the various components and hence calculate the accelerations involved - also we can solve it by considering the kinetic energy of the system. The latter approach is simpler to explain so this is the one shown below.
De hele verhandeling is te lezen op: http://www.pumaracing.co.uk/flywheel.htm (zeer de moeite van het lezen waard!)
Het is voor mij een item geworden op het lijstje van toekomstige tuningsplannen.
SteV6
Vliegwiel tuning; The do's and don'ts
Re: Vliegwiel tuning; The do's and don'ts
En nSteV6 schreef:Het volgende stukje tekst is genomen uit een artikel geschreven door David Baker.
LIGHTENING FLYWHEELS - AN EXERCISE IN ROTATIONAL DYNAMICS
When the flywheel of a car is lightened it can have a great effect on acceleration - much more than just the weight saving as a proportion of the total vehicle weight would account for. This is because rotating components store rotational energy as well as having to be accelerated in a linear direction along with the rest of the car's mass. The faster a component rotates, the greater the amount of rotational kinetic energy that ends up being stored in it. The engine turns potential energy from fuel into kinetic energy of motion when it accelerates a vehicle. Any energy that ends up being stored in rotating components is not available to accelerate the car in a linear direction - so reducing the mass (or more properly the "moment of inertia") of these components leaves more of the engine's output to accelerate the car. It can be useful to know how much weight we would need to remove from the chassis to equate to removing a given amount of weight from the flywheel (or any other rotating component). There is more than one way of solving this equation - we can work out the torque and forces acting on the various components and hence calculate the accelerations involved - also we can solve it by considering the kinetic energy of the system. The latter approach is simpler to explain so this is the one shown below.
De hele verhandeling is te lezen op: http://www.pumaracing.co.uk/flywheel.htm (zeer de moeite van het lezen waard!)
Het is voor mij een item geworden op het lijstje van toekomstige tuningsplannen.
SteV6
og eens 5kgvliegwiel
Binnenkort zit er bij ook een lichter vliegwiel in ,samen met een versterkte koppeling( motor moet er toch uit) dit scheelt bijna 5 kg
Dus dit zou betekenen in de eerste versnelling 200kg lichter en in de
tweede 60 kg en de derde nog steeds 30 kg.
Dus dit zou betekenen in de eerste versnelling 200kg lichter en in de
tweede 60 kg en de derde nog steeds 30 kg.